One thing the online test lacks is a good explanation of how the test is scored. I administered this test to all our employees and some were freaked out about seemingly high scores when they only misplaced a low number of patches. Here's a little background on how the Munsell Farnsworth Hue test is scored...
The number given as your score is not the number of colors out of position, but is a bit more complex than that. After all, you could have two immediately adjacent colors inverted, or two colors from opposite ends of the row inverted, with the latter being a more significant error than the first. Each color is assigned a number representing the order it should be placed (1, 2, 3, 4, ect). The score for a given color is the sum of the difference between it's number and the number of the two adjacent colors.
Cap Score (a
) = |a(n+1) - a
| + |a
- a(n-1)|
where a
is the number of the cap at position n in the sequence.
An example of a incorrectly ordered row:
Color Sequence:
10, 11, 12, 16, 15, 13, 14
Score:
x, 2, 5, 5, 3, 3, x
How Derived:
(1+1) (1+4) (4+1) (1+2) (2+1)
The minimum value for each correctly ordered color is 2. Then each row is scored by subtracting 2 times the number of colors in the row (equating a zero for a perfect row), and the total score is the sum of all 4 row scores. The number itself isn't as important as further analysis of the results, which the online version of this test gives in a graph.
To make is simpler, if you make one mistake, you score will be 3 or 4, and if you invert just 2 adjacent colors in each row (basically 1 mistake per row) your score will be 16. This isn't necessarily a bad score, but if the errors were all contained to one row, it would indicate considerable difficulty discerning between the particular hues in that row, and you might consider getting an MRI.
